- 【例52.1】 不与最大数相同的数字之和
1
- 2025-4-20 15:42:58 @
#include<bits/stdc++.h>
using namespace std;
int n;
int a[101],maxn=-1000001;
int main(){
cin>>n;
for(int i=0;i<n;i++){
scanf("%d",a+i);
if(maxn<*(a+i)){
maxn=*(a+i);
}
}
int sumn=0;
for(int i=0;i<n;i++){
if(*(a+i)!=maxn) sumn+=*(a+i);
}
printf("%d",sumn);
return 0;
}
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Information
- ID
- 232
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 8
- Tags
- # Submissions
- 219
- Accepted
- 31
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