- 练23.3 晶晶赴约会
关键
- @ 2026-1-22 15:41:52
if(a == 1 || a == 3 || a == 5) cout << "NO";
else cout << "YES";
1 comments
-
谭钧予 LV 9 @ 2026-5-13 20:21:23#include <bits/stdc++.h> using namespace std; int main(){ int x; cin>>x; if(x!=1&&x!=3&&x!=5) cout<<"YES"<<endl; else cout<<"NO"<<endl; return 0; }
- 1
Information
- ID
- 48
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 4
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